Question 700428
How can I find secant theta if tangent theta equals 8/15 and theta terminates in quadrant three?
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O=opposite side
A=adjacent side
H=hypotenuse
..
tan=O/A=8/15 (in quadrant III where sec<0
O=8
H=15
A=&#8730;(H^2-O^2)=&#8730;(225-64)=&#8730;161
sec=H/A
=15/&#8730;161
=(15&#8730;161)/161