Question 62416
The current population = 3000

Rate of increase every year = 0.6%
                            = 0.006

Population next year = 3000* 1.006

Population in the second year = 3000*1.006*1.006
                              = 3000*(1.006)^2


Thus the population 't' years from now would be = 3000*(1.006)^t

So p(t) = 3000*(1.006)^t 

 Good luck!!!