Question 62418

Let the exponential function be y = K p^x

Plugging in x = 1 and y = 4 in the above we get  4 = K p ------------(1)

Plugging in x = 2 and y = 8 in the above equation,

8 = K p^2 ------------------------(2)

Dividing (2) by (1) we get..
8/4 = K p^2/Kp

==> 2 = p

So the exponential function becomes..

y = K 2^x

Plugging in x = 5 and y = 64 in the above,

64 = K 2^5

==> 64 = 32K  [ 2^5 = 32]

==> 64/32 = 32k/32

==> 2 = k

Thus the constant rate of increase k = 2


Good Luck!!!