<PRE><B>Question 62327</B>
Given (1/3)(3y + 12) = – 5y – 4(y – 6) 

y + 4 =  -5y  -4y + 24

y + 4 =  - 9y + 24

y +  9y = 24 - 4

10 y = 20

y = 20 /10

y = 2


Solve for x: (4 + 3x)/5 + (7 – x)/3 = (7/15)

Given (4 + 3x)/5 + (7 – x)/3 = (7/15)

Multiply the above equation with 15, we get

(4 + 3x) *  3  + ( 7 - x) * 5 = 7

12 + 9x + 35 - 5x = 7

47 + 4x  -7 = 0

40 + 4x = 0

10 + x = 0

x = -10</PRE>