Question 62413
Consider equation(1), we get

2x - 3y = 0

2x = 3y 

x = 3y / 2  --->(3)

Substitute equation(3) in equation (2), we get

3 (3y / 2)  + 2y = 13

9y / 2 +  2y = 13

Mulitply by 2 throughout,we get


9y + 4y = 13 * 2

13 y = 13 * 2

y = 13 * 2 / 13

y = 2 --->(4)

Now substitue equation(4) in equation(3), we get

x = 3 * 2 / 2 = 3 --->(5)


Add equation (4) and eqaution(5)

We get x + y = 3 + 2 = 5

x +y = 5