Question 699685
How do I find the third degree polynomial equation with rational coefficients that has the given numbers as roots 
1) 5, 2i
-2i must also be a root.
f(x) = (x-5)(x-2i)(x+2i) 
= (x-5)(x^2+4)
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2)-7, i
-i must also be a root.
f(x) = (x+7)(x-i)(x+i)
= (x+7)(x^2+1)
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3)6, 3-2i
3+2i mult also be a root.
f(x) (x-6)[(x-3)+2i][(x-3)-2i]
= (x-6)[(x-3)^2+4]
= (x-6)(x^2-6x+13)
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Cheers,
Stan H.
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