Question 62410
Can you please help me factor 2t^2 - 19 - 6t=2t^2-6t-19
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (6+- sqrt( (-6)^2-4*2*(-19) ))/(2*2) }}}
{{{x = (6 +- sqrt( 36+152 ))/(4) }}}
{{{x = (3 +- sqrt( 47 ))/(2) }}}
hence the factors are 
[x-{3+sqrt(47)}/2][x-{3-sqrt(47)}/2]