Question 62402
31.) (a+3i)+(2+bi)=i 
Combine the Real number terms and the Complex number terms to get:
(a+2)+(3+b)i=0+1i
Equate the Real number of the left with the Real number on the right.
Do the same for the Complex number parts.
a+2=0 implies a=-2
3+b=1 implies b=-2
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33.) (5-the square root of -4)-(a+bi)=6 
(5-2i)-(a+bi)= 6 + 0i
(5-a)+(-2-b)i=6+0i
5-a=6 implies that a=-1
-2-b=0 implies that b=-2
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Cheers,
Stan H.