Question 699160
First you need to expand (multiply out) the brackets
Eg
{{{y=(9x^2+1)(3x+2)}}}
{{{y= 27x^3+18x^2+3x+2}}}
Now you can differentiate the expression to find the derivative.
So
{{{dy/dx= 81x^2+36x+3}}}
Now we can do a similar thing with the other equation
Unfortunately there's a problem! the second bracket contains (x-1-1) is that    (x-2)? or is it{{{(x^-1-1)}}}
I'll treat it like it's {{{(x^-1-1)}}}
So we have 
{{{y=(x^2+3)(x^-1-1)}}}
Let's expand the brackets
{{{y= x-x^2+3x^-1-3}}}
Now you can differentiate the expression to find the derivative.
{{{dy/dx = 1-2x-3x^-2}}}