Question 699171
"Pull out the pairs"
...
a. {{{sqrt(4x^8) = sqrt(2*2*x^4*x^4)}}}
therefore, 
{{{sqrt(4x^8) = highlight_green(2x^4)}}}
...
b. {{{sqrt(27a^3) = sqrt(9*3*a^2*a) = sqrt(3*3*3*a*a*a) = highlight_green(3a*sqrt(3a))}}}
……………….
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