Question 698920
Assume the problem is:
{{{7^((2x+1)) = 3^((x+2))}}}
using logs
{{{log(7^((2x+1))) = log(3^((x+2)))}}}
The log equiv of exponents
(2x+1)log(7) = (x+2)log(3)
Find the logs of 7 and 3
.8451(2x+1) = .4771(x+2)
1.6902x + .8451 = .4771x + .9542
1.6901x - .4771x = .9542 - .8451
1.213x = .1091
x = {{{.1091/1.213}}}
x ~ .09
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You can check this on your calc, replace x with .09 in the 1st equation, confirm they are equal