Question 698923
{{{3/2=1/2+1}}} and {{{5/2=1/2+2}}} so
x^(3/2) - x^(5/2) = x^(1/2+1) - x^(1/2+2) = (x^(1/2))(x^1) + (x^(1/2))(x^2) = (x^(1/2))(x^1+x^2) = (x^(1/2))({{{highlight(x+x^2)}}})