<PRE><B>Question 698758</B>
Solution:
LEt ABC is a triangle, with sides of measure, AB= c,AC = b,BC = a
the angle opposite of side 6 cm is x, 
now to find the angle with the given three sides, 
we can make use of the cosine rule which says that, 
a^2 = b^2 + c^2 - 2bc cos (B) 
6^2 = 9^2 + 5^2 - 2(9)(5)*cos x , 
36 = 81 + 25 - 90*cos (x) 
36 - 106 = -90*cos(x) 
-70 / -90 = cos (x) 
x = arccos( 7/9) 

Thanks 
Best regards.</PRE>