Question 698705
A number of two digits are equal to 6 times the sum of the digits, and the number formed by reversing the digits exceeds four times the sum of the digits by 9. what are the original numbers? 
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Let the number be 10t+u ( t is the ten's digit; u is the unit's digit)
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Equation:
10t+u = 6(t+u)
10u+t  = 4(t+u) + 9
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Rearrange:
4t -5u = 0
-3t+6u = 9
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Modify:
12t - 15u = 0
-12t +24u = 36
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Add and solve for "u":
9u = 36
u = 4
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Solve for "t":
12t = 15u
t = 15*4/12
t = 5
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Ans: The number is 10t+u = 54
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Cheers,
Stan H.
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