Question 698692
<pre>
Here it is in a little more detail

{{{matrix(2,1,"",ln(x))}}}{{{matrix(2,1,"",""-"")}}}{{{matrix(2,1,"",2*ln(x^2+1))}}}{{{matrix(2,1,"",""+"")}}}{{{matrix(2,1,"",expr(1/2)ln(3-x^4))}}}

Make the coefficients become exponents:

{{{matrix(2,1,"",ln(x))}}}{{{matrix(2,1,"",""-"")}}}{{{matrix(2,1,"",ln(x^2+1)^2)}}}{{{matrix(2,1,"",""+"")}}}{{{matrix(2,1,"",ln(3-x^4)^(1/2))}}}

Write the first two terms (the difference of two natural logs) as
the natural log of their quotient:

{{{matrix(2,1,"",ln(x/(x^2+1)^2))}}}{{{matrix(2,1,"",""+"")}}}{{{matrix(2,1,"",ln(3-x^4)^(1/2))}}}

Write those two terms (the sum of two natural logs) as
the natural log of their product:

{{{matrix(2,1,"",ln((x/(x^2+1)^2) (3-x^4)^(1/2)  ))}}}

Change the {{{1/2}}} exponent to a square root

{{{matrix(2,1,"",ln((x/(x^2+1)^2) sqrt(3-x^4)  ))}}}

and put the square root in the numerator multiplied by the x

{{{matrix(2,1,"",ln(   (x*sqrt(3-x^4))/(x^2+1)^2)  )}}}

Edwin</pre>