Question 698550
For this problem, you are selecting 2 girls from 6 to be at two positions in the line for girls, and selecting two boys from 5 to be at two positions in the line for boys. Since the order of the boys and girls in the line matters, calculate the values using permutations instead of combinations.<br>

The number of way to select k objects from n total objects when order is important is {{{nPk = n!/(n-k)!}}}. The number of total arrangements is equal to the number of ways to select the 2 girls times the numbers of ways to select the 2 boys.<br>

There are {{{6P2 = 6!/4! = 6*5 = 30}}} ways to select the two girls are the ends of the lines and {{{5P2 = 5!/3! = 5*4 = 20}}} ways to select the two boys in the middle. The number of total orderings is thus 30*20 = 600.