Question 698652
the formula becomes {{{(x-h)^2+(y-k)^2=r^2}}}

 where  {{{ h}}} and {{{k}}} are the {{{x}}} and {{{y}}} coordinates of the {{{center}}} of the circle, and {{{r}}} is radius


if given center ({{{1}}},{{{3}}})=({{{h}}} ,{{{k}}}) which means {{{h=1}}} and {{{k=3}}}, and radius of {{{r=2}}}, than equation will be



 {{{(x-1)^2+(y-3)^2=2^2}}}


 {{{(x-1)^2+(y-3)^2=4}}}