Question 698254
This problem can be solved using a combination (Use a combination instead of a permutation because the order the members are selected does not matter). The formula for a combination is<br>

{{{nCk = n!/(k!*(n-k!))}}}, where n is the number of possible objects to select from and k is the number of objects to select. Here, n = 15, and k = 12.<br>

{{{15C12 = 15!/(12!*(15-12!))}}}
{{{15C12 = 15!/(12!*(3!))}}}
{{{15C12 = (15*14*13)/(3*2*1) = 455}}}<br>

So, there are 455 possible juries that can be selected.