Question 62377
Solve:
{{{log(4)(x) = 1/2}}} The 4 here is the base of the logarithm.
You can rewrite this equation in exponental form according to the following:
{{{log(b)(x) = y}}} means {{{b^y = x}}} Applying this to your equation:
{{{log(4)(x) = 1/2}}} means:
{{{4^(1/2) = x}}} or
{{{sqrt(4) = x}}}
x = +/- 2