Question 698480


{{{(x-h)^2-(x-h)/h}}} when {{{x= -2}}} and {{{h =3}}}

={{{(-2-3)^2-(-2-(-3))/-3}}}

={{{(-5)^2-(-2+3)/-3}}}

={{{25-(1)/-3}}}

={{{25-(-1/3)}}}

={{{25+1/3}}}

={{{25+0.33}}}

={{{25.33}}}