Question 698471
find two positive numbers that satisfy the given requirements.
The second number is the reciprocal of the first and their sum is minimum.
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1st; x
2nd: 1/x
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Equation:
S(x) = x + (1/x)
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S(x) = (x^2+1)/x
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Take the derivative:
S'(x) = [x(2x)- (x^2+1)]/x^2
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Find the zeroes:
[2x^2 - x^2 - 1] / x^2 = 0
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(x^2-1) = 0
x = 1 or x = -1
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Max = 1+(1/1) = 2
Min = -1+ (1/-1) = -1-1 = -2
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Cheers,
Stan H.
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