Question 697952
solve the equation for 0 <= theta <= 2pi. 
write your answer as a multiple of pi, if possible
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2sin(theta)*cos (theta) + cos(theta) = 0
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Factor:
cos(theta)[2sin(theta)+1] = 0
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cos(theta) = 0 or sin(theta) = -1/2
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theta = pi/2 or (3/2)pi or (7/6)pi or (11/6)pi
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Cheers,
Stan H.
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