Question 698407
write the equation for the graph with vertex (-6,3) and focus (-6,0.25). 
This is a parabola that opens downwards.
Its standard form of equation: (x-h)^2=-4p(y-k), (h,k)=coordinates of vertex
Given vertex: (-6,3)
Axis of symmetry: x=-6
given focus:(-6,0.25)
p=3-.25=2.75 (distance from vertex to focus on the axis of symmetry)
4p=11
Equation:  (x+6)^2=-11(y-3) (ans. d)