Question 698427
A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3850 dollars. How much did he invest at each rate? 
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let x=amt invested at 10% rate
2x=amt invested at 6% rate
..
10%x+6%*2x=3850
0.10x+.12x=3850
.22x=3850
x=17500
2x=35000
amt invested at 10% rate=17500 dollars
amt invested at 6% rate=35000 dollars