Question 698452
Given: {{{0 = 4*n^2 + n}}}
You can factor out an n.
{{{0 = n*(4n + 1)}}}
Now you have to solve to find out what makes each part equal to zero.
The n on the out sides is easy: n = 0.
Now solve for 4n + 1 = 0
{{{4n + 1 = 0}}}
Subtract 1 from both sides
{{{4n = -1}}}
Divide both sides by 4
{{{highlight(n = -1/4)}}}
So n can be 0 or -1/4