Question 698422
{{{ 5y = x + 2 }}}
{{{ y = (1/5)*x + 2/5 }}}
Any line perpendicular to this line will have slope = {{{ -1/m }}}
where {{{ m }}} is the slope of the given line. In this case, {{{ m = 1/5 }}} 
{{{ -1/m = -5 }}}
Now given ( 2,0 ) and {{{ m = -5 }}},
I can write the general  point-slope formula:
{{{ ( y - 0 ) / ( x - 2 ) = -5 }}}
{{{ y = -5*( x - 2 ) }}}
{{{ y = -5x + 10 }}} answer
check:
Does it go through (2,0) ?
{{{ 0 = -5*2 + 10 }}}
{{{ 0 = -10 + 10 }}}
{{{ 0 = 0 }}}
OK