Question 698439
Equation of the circle centered at (1,8) that has a radius of 10: (x-1)^2 + (y-8)^2 = 100


You plug in y = 0 and solve for x


(x-1)^2 + (y-8)^2 = 100


(x-1)^2 + (0-8)^2 = 100


(x-1)^2 + (-8)^2 = 100


(x-1)^2 + 64 = 100


(x-1)^2 = 100-64


(x-1)^2 = 36


x-1 = sqrt(36) or x-1 = -sqrt(36)


x-1 = 6 or x-1 = -6


x = 6+1 or x = -6+1


x = 7 or x = -5


So the two points are (7, 0) and (-5, 0)