<PRE><B>Question 698003</B>
find the range of the following function: f(x)=(x+6)^2
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Since y = (x+6)^2 it cannot be negative.
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The smallest value it can have is zero; that occurs when x = -6.
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So the Range is ALL Real Numbers greater than or equal to zero.
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{{{graph(400,400,-10,10,-10,10,(x+6)^2)}}}
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Cheers,
Stan H.
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