<PRE><B>Question 698166</B>
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The sum of the measures of two complementary angles is 90 degrees, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ +\ 59\ +\ 40\ -\ 2d\ =\ 90]


Solve for *[tex \LARGE d], then calculate *[tex \LARGE d\ +\ 59] and *[tex \LARGE 40\ -\ 2d]. Report the larger value.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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