<PRE><B>Question 698163</B>
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Use the vertex form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ a\left(x\ -\ h\right)\ +\ k]


where *[tex \LARGE \left(h,\,k\right)] is the vertex.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ a\left(x\ -\ (-6)\right)\ +\ 2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ a\left(x\ +\ 6\right)\ +\ 2]


where *[tex \LARGE a\ \in\ \mathbb{R}].  Note that the equation is for a set of parabolas with infinite elements; one for each possible value of *[tex \LARGE a]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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