<PRE><B>Question 698051</B>
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&lt;b&gt;Step 1:&lt;/b&gt;  Change the relationship symbol to &quot;=&quot;.  Graph the resulting line. If the original relationship symbol was *[tex \LARGE &lt;] or *[tex \LARGE &gt;],  do it with a dashed or broken line.  If your symbol was *[tex \LARGE \leq] or *[tex \LARGE \geq], graph the equation with a solid line.


&lt;b&gt;Step 2:&lt;/b&gt;  Pick any point on the coordinate plane that &lt;b&gt;&lt;i&gt;does not&lt;/i&gt;&lt;/b&gt; lie on the line you just graphed. If the line does not pass through the origin, *[tex \Large (0,0)] then the origin is an excellent choice for this step.  If the line does pass through the origin, select a point other than the origin -- I recommend a point that has small integer coordinates.

  
&lt;b&gt;Step 3:&lt;/b&gt;  Substitute the values of the coordinates of the point chosen in Step 2 for the corresponding variables in the inequality you started with in Step 1.


&lt;b&gt;Step 4:&lt;/b&gt;  Do the appropriate arithmetic to determine whether the substitution created a true statement or not.  If you created a true statement, shade in the side of the line &lt;b&gt;&lt;i&gt;containing&lt;/i&gt;&lt;/b&gt; the point selected in Step 2.  If you created a false statement, shade in the side of the line that &lt;b&gt;&lt;i&gt;does not contain&lt;/i&gt;&lt;/b&gt; the selected point.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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