Question 698033
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Let *[tex \LARGE x] represent the first integer.  Then next consecutive integer is then *[tex \LARGE x\ +\ 1] and the third must be *[tex \LARGE x\ +\ 2].


Three times the second is then *[tex \LARGE 3(x\ +\ 1)].


The first added to three times the second is then *[tex \LARGE 3(x\ +\ 1)\ +\ x]


And the whole thing is equal to 83:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3(x\ +\ 1)\ +\ x\ =\ 83]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE x\ +\ 1] and *[tex \LARGE x\ +\ 2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
<font face="Math1" size="+2">Egw to Beta kai to Sigma</font>
My calculator said it, I believe it, that settles it
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