Question 698041
{{{((2i(4+5i)(4-5i)))/(4+i)}}}
FOIL
{{{((2i(16-25(i^2))))/(4+i)}}} = {{{((2i(41)))/(4+i)}}} = {{{(82i)/(4+i)}}}
Rationalize the denominator
{{{(82i)/(4+i)}}} * {{{(4-i)/(4-i)}}} = {{{(82i(4-i))/(16-(i^2))}}} = {{{(328i-82(i^2))/(16-(-1))}}} = {{{(328i-82(-1))/(17)}}} = {{{(82+328i)/(17)}}}