Question 697879
The probability mass function of the Poisson distribution is {{{P(X = x) = e^(-u)*((u^x)/x!)}}}. To find P(X = 0), plug in u = 6 and 0 = x into the probability mass function:<br>

{{{P(X = 0) = e^(-6)*((6^0)/0!)}}}
{{{P(X = 0) = e^(-6)*(1/1)}}}
{{{P(X = 0) = e^(-6) = .00248}}}