Question 62286
this is for college algebra graph: 
{{{F(x)=-2/(x-3)}}}
The degree of the denominator (bottom) is higher than the degree of the numerator (top).  Therefore there is a horizontal asymptote of y=0. That means the graph is approaching 0 when you go to the left and right.
There is a vertical asymptote where it is undefined at x-3=0 --> x=3.  That means there is an invisible vertical line at x=3 that the graph doesn't equal.  Unfortunately, this program and any calculator below the Ti-84 draws the vertical asymptotes in.
Pick points to the left and right of x=3 to graph:
When x=0
y=-2/(0-3)
y=2/3  Plot (0,2/3)
When x=2
y=-2/(2-3)
y=-2/-1
y=2  Plot (2,2)
When x=4
y=-2/(4-3)
y=-2/1
y=-2  Plot (4,-2)
When x=5
y=-2/(5-3)
y=-2/2
y=-1  Plot (5,-1)
Your graph looks like this, you'll need to remove the vertical asymptote at x=3.
{{{graph(300,200,-10,10,-10,10,-2/(x-3))}}}
Happy Calculating!!!