Question 7791
{{{(x + 1)^2}}}= 9
(x+1)(x+1)=9
{{{x^2+2x+1=9}}}
{{{x^2+2x-8=0}}}
(x-2)(x+4)=0
*****if x-2=0, x=2
*****if x+4=0, x=-4


{{{( 3x + 2 )^2}}}=49
(3x+2)(3x+2)=49
{{{9x^2+6x+6x+4=49}}}
{{{9x^2+12x-45=0}}}
{{{3(3x^2+4x-15)=0}}}
{{{3(x+3)(3x-5)=0}}}
*****if x+3=0, then x=-3
*****if 3x-5=0, then x={{{3/5}}}