Question 697483
Find the roots of the equation by quadratic formula							
							
a=	3	b=	-4	c=	-6		
							
b^2-4ac=	16	-	-72				
b^2-4ac=	88			{{{sqrt(	88	)}}}=	9.38
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(	4	+	9.38	)/	6		
x1=	2.230						
x2=(	4	-9.38	) /	6			
x2=	-0.897						
				
x	=	2.23	OR -0.90