Question 697461
Find the two consecutive positive integer such that the sum of their squares is 145.
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1st: x
2nd: x+1
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Equation:
x^2 + (x+1)^2 = 145
x^2 + x^2 + 2x + 1 = 145
2x^2 + 2x - 144 = 0
x^2 + x - 72 = 0
Factor:
(x+9)(x-8) = 0
Positive solution:
x = 8
x+1 = 9
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Cheers,
Stan H.