Question 697448

you know that a perimeter of a rectangle is 

{{{P=2(L+W)}}}

if flat rectangular piece of aluminum has a perimeter of {{{60in}}}, means

{{{2(L+W)=60in}}}

if the length is {{{14in}}} {{{longer}}} than the {{{width}}}, we can write it as

{{{L=W+14in}}}.......now substitute {{{L}}} in {{{2(L+W)=60in}}}


{{{2(W+14in+W)=60in}}}...solve for {{{W}}}

{{{W+14in+W=60in/2}}}

{{{2W+14in=30in}}}

{{{2W=30in-14in}}}

{{{2W=16in}}}

{{{W=16in/2}}}

{{{highlight(W=8in)}}}


now go back to {{{L=W+14in}}}, plug in {{{W}}} and solve for {{{L}}}


{{{L=8in+14in}}}


{{{highlight(L=22in)}}}