Question 7818
2(w-3)+5=3(w-1)
(2)(w)+(2)(-3)+5=(3)(w)+(3)(-1)
2w-6+5=3w-3
2w-1=3w-3
(2w-1)-2w=(3w-3)-2w
-1=w-3
(-1)+3=(w-3)+3
2=w