Question 697335
{{{log(x^a) = a*log(x)}}}, so {{{log(x^6) = 6*log(x)}}}.

{{{5 + log(x) = 6*log(x)}}}, subtract log(x) from both sides:
{{{5 = 5*log(x)}}}, divide both sides by 5:
{{{1 = log(x)}}}. Since log with no base given usually denotes log base 10, you want the value of x for which:

{{{10^1 = x}}}, so x = 10.