Question 7821

{{{-1/4}}}(-32x=40y)
8x=40y
(8x){{{(1/8)}}}=(40y){{{(1/8)}}}
x=5y


x=5y
{{{(1/5)}}}x=5y{{{(1/5)}}}
{{{x/5}}}=y



3(x+4y)+(-4)(8x-y)
=(3)(x)+(3)(4y)+(-4)(8x)+(-4)(-y)
=3x+12y-32x+4y
=-29x+16y