Question 697058
(1)x^2-x=6=====================problem
x^2-x-6=0====move terms to one side
(x-3)(x+2)=0======factor
(x-3)=0   OR (x+2)=0=====solve
x=3  OR X=-2=========SOLUTION

(2)√2x-3+1=4==========problem
√2x=6
x=3√2
x=18=========solve by factoring