Question 697083
b(1)=2/(2^1)=2/2=1
b(2)=(2*4)/(2^2)=2
b(3)=(2*4*6)/(2^3=8*6/8=6
b(4)=(2*4*6*8)/(2^4)=2*4*6*8/16=4*6=24
ok,i did the first 4 terms for you,follow the pattern to get your last 2 terms
in that way you will see how easy it is for you to understand