Question 697274
a chemist wants to mix a 22 acid solution with a 50 acid solution to get 28 l of a 30 acid solution. how many liters of the 22% solution and how many liters of the 50% solution should be mixed?
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let x=amt of 22% acid solution to mix
(28-x)=amt of 50% acid solution to mix
22%x+50%(28-x)=30%*28
.22x+14-.5x=8.4
.28x=5.6
x=20
28-x=8
amt of 22% acid solution to mix=20 liters
amt of 50% acid solution to mix=8 liters