Question 697281
You are doing OK.
Keep on going.
You have to solve for y.
You should end up with
{{{y=(1/2)x-1/2}}} (answer I would prefer)
{{{y=(1/2)(x-1)}}} and {{{y=x/2-1/2}}} are alternative equivalent answers.
 
Here's how you would solve for y:
{{{x=2y+1}}} --> {{{x-1=2y+1-1}}} --> {{{x-1=2y}}} (subtracting 1 from both sides of the equal sign)
{{{x-1=2y}}} --> {{{(x-1)/2=2y/2}}} --> {{{(x-1)/2=y}}} (dividing both sides by 2)
{{{(x-1)/2=y}}} is the same as {{{y=(x-1)/2}}} because the equal sign works both ways, 
and {{{y=(x-1)/2}}} is the same as {{{y=(1/2)(x-1)}}} because dividing by 2 is the same as multiplying by 1/2.
{{{y=(1/2)(x-1)}}} --> {{{y=(1/2)x+(1/2)(-1)}}} --> {{{y=(1/2)x-1/2}}} (applying the distributive property)
{{{y=(1/2)x-1/2}}} --> {{{y=x/2-1/2}}} because dividing by 2 is the same as multiplying by 1/2, so that {{{(1/2)x=x/2}}}.