Question 62253
(2x+3y)^3
The form is (a+b)^3=a^3+3a^2b+3ab^2+b^3
In your case a=2x and b=3y so you get:
(2x)^3+3(2x)^2(3y)+3(2x)(3y)^2+(3y)^3
=8x^3+36x^2y+54xy^2+27y^3
Cheers,
Stan H.