Question 62254
What is the solution for (3x-8)(2x+1)
Distribute the first term in the 1st parentheses into the second parentheses, then the second term into the second parentheses.
3x(2x+1)-8(2x+1)
This is sometimes called FOIL because you are multiplying the First terms, Outer terms, Inner terms, and Last terms in each parentheses.
3x(2x)+3x(1)-8(2x)-8(1)
{{{3x^2+3x-16x-8}}}  Combine your like terms.
{{{highlight(3x^2-13x-8)}}}
Happy Calculating!!!