Question 697172
You must add the rates of twisting for each
of the machines to get their rate working together.
Let {{{ t }}} = the time to fill daily quota with all
three machines running
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The old machine's rate is ( 1 daily quota ) / ( 20 hrs ) = {{{ 1/20 }}}
If the New machine's rate is twice the old one's, then it can do
( 1 daily quota ) / ( 10 hrs ) = {{{ 1/10 }}}
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With all 3 machines running:
{{{ 1/20 + 1/20 + 1/10 = 1/t }}}
{{{ 2/20 + 1/10 = 1/t }}}
{{{ 2/20 + 2/20 = 1/t }}}
{{{ 1/t = 4/20 }}}
{{{ 1/t = 1/5 }}}
{{{ t = 5 }}}
It will take 5 hrs to fill daily quota with all
three machines running