Question 697148
solve by completing the square:

{{{x^2-4x+10=0}}}

My work:

{{{x^2-4x=-10}}}   then do half of four which is 2, then do 2times 2 and get 4.
{{{X^2-4x+4=-10+4}}}
{{{X^2-4x+4=-6}}}
(x-2)(x-2)=-6
{{{x-2 = sqrt(-6)}}}
{{{x = 2 + i*sqrt(6)}}}
{{{x = 2 - i*sqrt(6)}}}
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i = sqrt(-1)
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(x-2)=plus or mine {{{sqrt(6)}}}
x=2 plus or minus {{{sqrt(6)}}}  ***** correct except for the i